Thursday, July 20, 2006

Riddle!

Ok folks, inspired by my friend...from now onwards I shall post riddles for you peepz to try solving them till I ran out of them...

Here goes the first of the series...

A man was walking down the street, when he bumped into his long lost friend.
After the usual how-are-you-i-am-fine bullcrap, the friend asked if the man had any children.

Friend: "Do you have any children?"
Man: "Yes. 3 sons."
Friend: "How old are they?"

Being cheeky, the man refused to tell him outright. So he said...
Man: "If you multiply their ages together, you get 36" (e.g. 9x4x1)
Friend: "Hmm...there are quite a few possibilities."
Man: "If you add their ages together, you get the number of houses opposite the street."

The friend looked across the street, thought for a moment and said...
Friend: "Impossible to tell yet, I need just one more clue."
Man: "Hmm...my eldest son plays the piano."
Friend: "Ahh...I get it now!"

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BIG QUESTION: How old are the 3 children? =)
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Very Important Assumptions:
1) Age is strictly in years.
2) Eldest son's age is greater than each of the other two sons'.
3) Friend is smart.

2 Comments:

At 9:19 PM, Blogger jL-yZ said...

Looks like nobody bothered answering or managed to answer...

Anyhow, here's a hint...


my ELDEST son plays a piano = There's an ELDER son whom by assumption is older than each of the other sons by at least 1 year old...

Hope that helps! Cheers =)

 
At 11:53 PM, Blogger jL-yZ said...

weishiong: answer is 9 2 2 cuz all the combis add up to diff ans except for 661 and 922 = 13 figure the rest...

 

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